MATH133_U5_answer - b y=log-x is a reflection over the...

Info icon This preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon
NAME: ___Jeremy Dellinger_________________________ Student Answer form Unit 5; show all work for full credit; trial and error (guess and check) methods are not appropriate; use methods covered in class. 1. a. t=20ln(1600) t≈147.552 b. x=e^3/4 c. 2^5=8-6x 32=8-6x 6x=8-32=-24 x=-4 d. e^(-x)= -4/5 2. a. horizontal shift to the left by 5 units log(x)=0 x= -5 x-intercept: set y=0 0 = log(x+5) x+5=10^0 x+5=1 x=-4 (-4,0) is the x-intercept y-intercept: set x=0 y= log(5) (0, log(5) is the y-intercept
Image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Image of page 2
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: b. y=log(-x) is a reflection over the y-axis of y=logx vertical—x=0 3. a. 50=68-20log(t+1),t≥0-18=-20*log(t+1) 0.9=log(t+1) t+1=10^0.9 t=6.943 months b. 4 months—54% 24 months—40% c. 6.9 months is when the average score was 50% 4. a. A=P(1+r)^nt A=2000(1+.08)^5 A=2000(1.46933) A=$2938.65 b. A=2000(1+.08/4)^4*5 A=2000(1.02)^20 A=2000(1.485947) A=$2971.89 c. A=Pe^rt A=2000(2.7183)^.08*5 A=2000(1.491828687) A=$2983.67...
View Full Document

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern