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Unformatted text preview: 5. Determine the value of Q enc from your figure and insert it into Gauss's equation. 6. Solve the equation for the magnitude of E . Under electrostatic conditions, any excess charge resides entirely on the surface of a solid conductor. Gaussian surface E = 0 Application of Gauss’s Law to conductors: The solution of this problem lies in the fact that the electric field inside a conductor is zero and if we place our Gaussian surface inside the conductor (where the field is zero), the charge enclosed must be zero (+ q – q) = 0. Symmetries Planar Spherical Cylinderical Electric field between two oppositely charged parallel plates. Some Useful results: The electric field of a uniformly charged INSULATING sphere....
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This note was uploaded on 05/30/2011 for the course PHYS 150 taught by Professor Anzmeador during the Spring '08 term at EmbryRiddle FL/AZ.
 Spring '08
 AnzMeador
 Physics

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