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ME211solution_3 - In case of using method of joints the...

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In case of using method of joints the supporting reactions are not required. Joint B: 3 0; cos45 100 0 5 x BC BA F F F = ° − = ------① 4 0; sin45 500 0 5 y BC BA F F F = ° + = = = b ------② Solving Eqs. ① and ② yields 286 BA F lb = (T) 384 BC F lb = (T) Joint C: 0; 384cos45 0 x CA F F = ° 271 CA F lb = (C) B C 0; 384sin45 0 y y F C = ° 271.43 y C l =
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