Bus 515 ch5 Problems

Bus 515 ch5 Problems - R2 = 0.89 + (0.80 x 0.11) = 0.978 R3...

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Rami Dirani Strayer University Bus 515 Operation Management Winter 2011 Ch5 problems (2-4-6-8-10) Problem # 2 The reliability of the engine is (0.998)x(0.998)x(0.998)x(0.998)x(0.998)x(0.998)x(0.998)x(0.998)x(0.998)x(0.998) = (0.998) 10 = 0.9801790 Problem # 4 R 3 = 0.998 R = 0.998 (1/3) = 0.9993328 Problem # 6 Let’s find the reliability of each component first R1 = 0.90 + (0.80 x 0.1) = 0.98
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Unformatted text preview: R2 = 0.89 + (0.80 x 0.11) = 0.978 R3 = 0.95 + (0.80 x 0.05) = 0.99 Now we can calculate the reliability of the entire system: R = R1 x R2 x R3 = 0.98 x 0.978 x 0.99 = 0.9488556 Problem # 8 R 5 = 0.998 R = 0.998 (1/5) = 0.9995996 Problem # 10 R = 0.90 x (0.85 + (0.85x0.15)) x ((0.90 + (0.90 x 0.1)) x 0.95 = = 0.90 x 0.9775 x 0.99 x 0.95 = 0.8274048...
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Bus 515 ch5 Problems - R2 = 0.89 + (0.80 x 0.11) = 0.978 R3...

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