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Unformatted text preview: NAME: KEY E MCH 210H Statics and Strength of Materials Section 1 (1:252:15)
Fall 2010 Section 2 (2:303:20)
Exam 2 This is a closed book exam. Show all of your work in a clear and logical progression. Partial credit will be
based on the clarity of the work shown. If the instructor can’t read your work, you can’t get credit for it.
Clearly mark your answers and include units. Check your work. The exam has four pages and a cover sheet. Let the instructor know immediately if your exam has less
pages or if anything is illegible. Good luckl P V 6  ﬂ
. (“=2 1m:2 O'=E8 EA
1. of 10 6 6 — 81m = vs 0m = K 5
2. of 10 em = 7M = 1 = G7 A
3. of 10 g = “AT FS = failure/ actual
T
4. 0f 10
—_ 0'“ = ﬂ O'h = ﬂ
TOTAL of 40 T = T_P P = Ta, 2’ t
J
TL
6 = — co = 2
G] if
7:
J = 3(44  n“) 1 hp = 33000 ftlb/min
1 W = 1 Nm/s . IIIII
'2 IIIIII. IllIII IREIII “NamIII
Iﬂﬁ‘aIIIIII Stress concentration factor K,
Stress concentration factor K,
Stress concentration factor K, Figure 520 Stress concentration factors for grooves. holes, and ﬁllets. NAME: 1. A pinned connection transmits a 15 kN force from member A to member B. A shear stressstrain curVe
for the material used for the pin is shown. Determine: (a) the diameter, d, of the pin, to the whole millimeter, to provide a factor of safety of 1.8,
(b) the bearing stress from the pin at the face of the hole in member B,
(c) the punching shear stress in member 8. 5mm
~—» 5m I Top View
Pin diameter, d P=15kN
50mm
15mm
SideView
in FED "H
PI;
UaP —*V
Pl; <— V: War"(.5 kN
+0.5
(R, _
1... T.
[E0 ‘ ?—v P
bio—37M“
P leooo :E—E'l'b P
_" "'_ (a)d= 0 mm
K\ mm
n. ISOOD (b)Bearing= \50 MPA
L "' 205‘ 10" " 50 MPa +3 ' (c)Punching= 50 MPOL NAME: 2. A 3” diameter concrete cylinder surrounds a 0.5” diameter steel bar. The concrete is perfectly bonded to the steel bar. At 60°F the materials are stress free and 36” long. After the temperature has
raised to 180°F and a compressive force of 4000 lb is applied. Determine: (a) the stress in the concrete
(b) the stress in the steel (c) the change in length of the assembly. been Steel rod: D = 0.5", E = 30x106 psi, (1 = 8x10“ 1/°F A; 3&2
Concrete cylinder: D0 = 3", D, = 0.5", E = 3x106 psi, (1 = 4x10'6 1/°F : 0MB m
A6 = Mal—9.5% t 9.3—, xma +\
F3!) 'Dexcarm. Compoi.
$F=Looo lb 86 ___ 5‘ +1 WK _ \ {I
r! [ S " lPs
‘11P“ ( '\>\ P
’ Limbo—v C y; c z
.. l —  I — = \ \
.0, 95443; Hooo 30mg(ol‘%3\ + gm) (l80 (go) Mama?“ 4390/9030;
+9.
—o.\s%(4ooo+Pe\ + %o = 0.0435 Pc '+ 4E0
mq'a = 0.905%
Pr, = " cll'rl lb +l
40%  —e 1
= ——————" + mo l (36\ _
SS [wrinklwqéﬁ 8 (ac) c: 35— : —\‘53.0 Psi +l
(4561
—c
e (— 594 + 9eo\ 36W)
P5 —— — (4000+ PA = — 30% H1:
=+o.e\61o" +\
30% .
= = i ‘7 5L
5 olmég ‘3, 80 P (a) '133.0 gs: (b) name psi
(c) +(9.0(670” NAME: 3. A motor attached at C to the shaft shown and rotating at a speed of 1000 rpm drives two devices
through belts connected to the steel shaft at A and B. Determine the maximum power (in horsepower)
that can be delivered to the device attached at A if the maximum shearing stress in the shaft must not
exceed 18 ksi and the rotation of end A with respect to end C must not exceed 3 degrees. The hollow
section rigidly attached at B to the solid section from B to C. Steel: E = 29 x 103 ksi, G = 11 x 103 ksi
AB outer diameter = 3 in.
AB inner diameter = 1.5 in. BC diameter = 2.5 in. 41” : i3(3$3\ _
» L95 .— .6“
=7 \= ~11 ll
5
L4
.0
K
i.
5 ’IT anew" “Kt 9mm: BOT2‘0.“ = éAB 'l’ 98(
11:. = TLBIl>\ 4TV0'V3\
O Waco (1.4% H .000 (3,8 3\ T] (.ll1000\ =——+ (000% 1% 3&3 = “Lll ps'm . ‘ h E h
E! 971’ rad P = loci.
P: @320 lb‘mlﬁijln \600 min‘ rev 33600 “rib/min P Maximum Power at A, P = quX (report in horsepower) NAME: 4.1 Match the letters (AE) shown on the stressstrain curve from a tension test conducted on an
aluminum alloy with the appropriate material parameter. Not all material parameters are shown on the
stressstrain curve. 0 _D_1. Elongation __Q_2. Proportional limit
__B__3. Young’s modulus __’_4. Poisson’s ratio _A_5. Ultimate strength + l
__f_6. Modulus of rigidity E .
D E 8 7. Yield strength + l 4.2 A w=1” wide plate that is t=0.125” thick and has two d=0.25" diameter holes is loaded as shown.
Calculate the maximum stress in the plate. /t\ I %=9%=0.95 1200 lb ‘3_ 700 lb \300 $139.9“...
3335 (“936309.139 H = 30,030 psi +51 4.3 A cylindrical pressure vessel has an inner radius r = 1.2 m, a wall thickness t = 6 mm, and contains an
internal pressure of 0.3 MPa. Calculate the normal stresses in the vessel wall and sketch how they act on
the pressure vessel. r \i‘ a 50 MPa Jc 0.004 l ': 300 > L0 <31: ﬁg = mama. (90 m End cap GA: ﬁt a @ ...
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 Spring '11
 C.J.Lissenden,

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