This preview shows page 1. Sign up to view the full content.
Unformatted text preview: have 10 * 0.2 = 2 successes. The spread of a binomial distribution is not so intuitive, so we will not justify our formula for standard deviation. If sample count X of successes is a binomial random variable for n fixed observations with probability of success p for each observation, then X has a mean and standard deviation as discussed in section 8.4 of: Mean = np and standard deviation = And as long as the above 2 requirements are for n and p are satisfied, we can approximate X with a normal random variable having the same mean and standard deviation and use the normal calculations discussed previously in these notes to solve for probabilities for X....
View
Full
Document
This note was uploaded on 05/31/2011 for the course STAT 200 taught by Professor Andyregards during the Spring '11 term at World College.
 Spring '11
 AndyRegards
 Binomial

Click to edit the document details