1.) Projectile:
At t = 0, an object is projected with a speed v0 = 45 m/s at an angle q0 = 21.8° above the
horizontal. The axes on the diagram show the x and y directions that are to be considered positive.
For parts ag, calculate the requested quantities at t = 10 s into the flight. (Use 9.81 m/sec2 for g.)
a) The vertical acceleration of the object:
ay =
m/s2
*
9.81
OK
b) Its horizontal acceleration:
ax =
m/s2
*
0
OK
c) Its vertical velocity:
vy =
m/s
*
81.38
OK
d) Its horizontal velocity:
vx =
m/s
e) The angle to the horizontal at which the object is traveling (an angle above the horizontal should be
reported as a positive number; an angle below the horizontal should be reported as a negative number).
Please give your answer in degrees:
angle =
°
f) Its vertical displacement, from where it started:
y =
m
g) Its horizontal displacement, from where it started:
x =
m
h) At what time does the object reach its maximum height?
ty, max =
This preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
This is the end of the preview. Sign up
to
access the rest of the document.
 Summer '10
 MORAN
 Velocity, m/s, vy

Click to edit the document details