ch14-p010 - 10. Note that 0.05 atm equals 5065 Pa....

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10. Note that 0.05 atm equals 5065 Pa. Application of Eq. 14-7 with the notation in this problem leads to max liquid liquid liquid 0.05 atm 5065 Pa p d gg g ρρ ρ == = . Thus the difference of this quantity between fresh water (998 kg/m
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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