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On the other hand, the gauge pressure at an altitude of 7.6 km is
32
4
2a
i
r
(0.87 kg/m )(9.8 m/s )(7600 m)
6.48 10 Pa
pg
h
ρ
==
=
×
.
Therefore, the change in pressure is
54
5
12
2.00 10 Pa 6.48 10 Pa
1.4 10 Pa
ppp
Δ= − =
×
−
×
≈ ×
.
14. Using Eq. 147, we find the gauge pressure to be
gauge
p
gh
=
, where
is the
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics

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