This preview shows page 1. Sign up to view the full content.
19. When the levels are the same the height of the liquid is
h
= (
h
1
+
h
2
)/2, where
h
1
and
h
2
are the original heights. Suppose
h
1
is greater than
h
2
. The final situation can then be
achieved by taking liquid with volume
A
(
h
1
–
h
) and mass
ρ
A
(
h
1
–
h
), in the first vessel,
and lowering it a distance
This is the end of the preview. Sign up
to
access the rest of the document.
 Spring '08
 Any
 Physics, Mass

Click to edit the document details