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Unformatted text preview: Assuming the pressure at the surface can be taken to be zero (in the gauge pressure sense explained in section 144), then this means the force on the wall is 1 2 gh multiplied by the appropriate area. In this problem the area is hw (where w is the 8.00 m width), so the force is 1 2 gh 2 w , and the change in force (as h is changed) is 1 2 gw ( h f 2 h i 2 ) = 1 2 (998 kg/m 3 )(9.80 m/s 2 )(8.00 m)(4.00 2 2.00 2 )m 2 = 4.69 10 5 N....
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics, Force

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