Ch14-p035 - V/3 to obtain b = 2 w/3 = 2(1000 kg/m 3/3 ≈ 6.7 × 10 2 kg/m 3(b If o is the density of the oil then Archimedes’ principle yields o

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35. (a) Let V be the volume of the block. Then, the submerged volume is V s = 2 V /3. Since the block is floating, the weight of the displaced water is equal to the weight of the block, so ρ w V s = b V , where w is the density of water, and b is the density of the block. We substitute V s = 2
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Unformatted text preview: V /3 to obtain b = 2 w /3 = 2(1000 kg/m 3 )/3 ≈ 6.7 × 10 2 kg/m 3 . (b) If o is the density of the oil, then Archimedes’ principle yields o V s = b V . We substitute V s = 0.90 V to obtain o = b /0.90 = 7.4 × 10 2 kg/m 3 ....
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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