ch14-p036 - direction is upward). Let h = 0.500 m. Then,...

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36. Work is the integral of the force (over distance – see Eq. 7-32), and referring to the equation immediately preceding Eq. 14-7, we see the work can be written as W = water ρ ³ gA (– y ) dy where we are using y = 0 to refer to the water surface (and the + y
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Unformatted text preview: direction is upward). Let h = 0.500 m. Then, the integral has a lower limit of – h and an upper limit of y f , with y f / h = − cylinder / ρ water = – 0.400. The integral leads to W = 1 2 water gAh 2 (1 – 0.4 2 ) = 4.11 kJ ....
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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