ch14-p042 - F b = (0.25 N – 0.10 N ) = 0.15 N. Thus, ρ...

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42. From the “kink” in the graph it is clear that d = 1.5 cm. Also, the h = 0 point makes it clear that the (true) weight is 0.25 N. We now use Eq. 14-19 at h = d = 1.5 cm to obtain
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Unformatted text preview: F b = (0.25 N – 0.10 N ) = 0.15 N. Thus, ρ liquid g V = 0.15, where V = (1.5 cm)(5.67 cm 2 ) = 8.5 × 10 − 6 m 3 . Thus, liquid = 1800 kg/m 3 = 1.8 g/cm 3 ....
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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