This preview shows page 1. Sign up to view the full content.
51. This problem involves use of continuity equation (Eq. 1423):
11
2 2
Av
=
.
(a) Initially the flow speed is
1.5 m/s
i
v
=
and the crosssectional area is
i
AH
D
=
. At
point
a
, as can be seen from Fig. 1447, the crosssectional area is
()
(
)
a
h
D
b
h
d
=−
−
−
.
Thus, by continuity equation, the speed at point
a
is
(14 m)(55 m)(1.5 m/s)
2.96 m/s
(
)
(
)
(14 m 0.80 m)(55 m) (12 m 0.80 m)(30 m)
This is the end of the preview. Sign up
to
access the rest of the document.
 Spring '08
 Any
 Physics

Click to edit the document details