51. This problem involves use of continuity equation (Eq. 14-23): 112 2Av=.(a) Initially the flow speed is 1.5 m/siv=and the cross-sectional area is iAHD=. At pointa, as can be seen from Fig. 14-47, the cross-sectional area is ()()ahDbhd=−−−.Thus, by continuity equation, the speed at point ais(14 m)(55 m)(1.5 m/s)2.96 m/s()()(14 m 0.80 m)(55 m) (12 m 0.80 m)(30 m)
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