51. This problem involves use of continuity equation (Eq. 1423):
11
2 2
Av
=
.
(a) Initially the flow speed is
1.5 m/s
i
v
=
and the crosssectional area is
i
AH
D
=
. At
point
a
, as can be seen from Fig. 1447, the crosssectional area is
()
(
)
a
h
D
b
h
d
=−
−
−
.
Thus, by continuity equation, the speed at point
a
is
(14 m)(55 m)(1.5 m/s)
2.96 m/s
(
)
(
)
(14 m 0.80 m)(55 m) (12 m 0.80 m)(30 m)
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics

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