ch14-p052 - This implies that the speed in the middle...

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52. The left and right sections have a total length of 60.0 m, so (with a speed of 2.50 m/s) it takes 60.0/2.50 = 24.0 seconds to travel through those sections. Thus it takes (88.8 – 24.0) s = 64.8 s to travel through the middle section.
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Unformatted text preview: This implies that the speed in the middle section is v mid = (110 m)/(64.8 s) = 0.772 m/s. Now Eq. 14-23 (plus that fact that A = r 2 ) implies r mid = r A (2.5 m/s)/(0.772 m/s) where r A = 2.00 cm. Therefore, r mid = 3.60 cm....
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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