()
22
21
12
53
2
2
3
2
5
1
2
1
1.5 10 Pa
(1000kg m ) (5.0m s)
(2.5m s)
(1000kg m )(9.8m/s )(10 m)
2
2.6 10 Pa.
pp
vv
g
h
h
ρρ
=+
− +
−
ªº
=×
+
−
+
¬¼
55. (a) We use the equation of continuity:
A
1
v
1
=
A
2
v
2
. Here
A
1
is the area of the pipe at
the top and
v
1
is the speed of the water there;
A
2
is the area of the pipe at the bottom and
v
2
is the speed of the water there. Thus
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics

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