()22211253223251211.5 10 Pa(1000kg m ) (5.0m s)(2.5m s)(1000kg m )(9.8m/s )(10 m)22.6 10 Pa.ppvvghhρρ=+− +−ªº=×+−+¬¼55. (a) We use the equation of continuity: A1v1= A2v2. Here A1is the area of the pipe at the top and v1is the speed of the water there; A2is the area of the pipe at the bottom and v2is the speed of the water there. Thus
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.