whereh1is the height of the water in the tank, p1is the pressure there, and v1is the speed of the water there; h2is the altitude of the hole, p2is the pressure there, and v2is the speed of the water there. ρis the density of water. The pressure at the top of the tank and at the hole is atmospheric, so p1= p2. Since the tank is large we may neglect the water speed at the top; it is much smaller than the speed at the hole. The Bernoulli equation then becomes 211222ghvghρρ=+and ()221222 9.8m s0.30m2.42m s.vghh=−==The flow rate is A2v2= (6.5 ×10–4m2)(2.42 m/s) = 1.6 ×10–3m3/s.(b) We use the equation of continuity:
This is the end of the preview. Sign up
access the rest of the document.
This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.