ch14-p065

# ch14-p065 - 65. (a) Since Sample Problem 14-8 deals with a...

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Thus, one root is related to the other (generically labeled h' and h ) by h' = H h . Its numerical value is ' 40cm 10 cm 30 cm. h =− = (c) We wish to maximize the function f = x 2 = 4 h ( H h ). We differentiate with respect to h and set equal to zero to obtain 48 0 2 df H Hh h dh = ¡ = or h = (40 cm)/2 = 20 cm, as the depth from which an emerging stream of water will travel the maximum horizontal distance. 65. (a) Since Sample Problem 14-8 deals with a similar situation, we use the final equation (labeled “Answer”) from it: 0 2 for the projectile motion. vg hv v = ¡ = The stream of water emerges horizontally ( θ 0 = 0° in the notation of Chapter 4), and setting y y 0 = –( H h ) in Eq. 4-22, we obtain the “time-of-flight” 2( ) 2 () . tH h gg −− == Using this in Eq. 4-21, where x 0 = 0 by choice of coordinate origin, we find 0 2( ) 2 2 (
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## This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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