ch14-p073 - magnitude F g = m glass g. Application of...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
73. The normal force N F G exerted (upward) on the glass ball of mass m has magnitude 0.0948 N. The buoyant force exerted by the milk (upward) on the ball has magnitude F b = ρ milk g V where V = 4 3 π r 3 is the volume of the ball. Its radius is r = 0.0200 m. The milk density is ρ milk = 1030 kg/m 3 . The (actual) weight of the ball is, of course, downward, and has
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: magnitude F g = m glass g. Application of Newton's second law (in the case of zero acceleration) yields F N + milk g V m glass g = which leads to m glass = 0.0442 kg. We note the above equation is equivalent to Eq.14-19 in the textbook....
View Full Document

This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

Ask a homework question - tutors are online