ch15-p013 - 13. When displaced from equilibrium, the net...

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13. When displaced from equilibrium, the net force exerted by the springs is –2 kx acting in a direction so as to return the block to its equilibrium position ( x = 0). Since the acceleration 22 / ad xd t = , Newton’s second law yields =2. 2 2 m dx dt kx Substituting x = x m cos( ω t
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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