ch15-p015 - 15. (a) Eq. 15-8 leads to a 123 m/s 2 = = =...

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15. (a) Eq. 15-8 leads to 2 2 123 m/s 35.07 rad/s . 0.100 m a ax x ωω =− ¡ == = Therefore, f = ω /2 π = 5.58 Hz. (b) Eq. 15-12 provides a relation between (found in the previous part) and the mass: 2 400 N/m = 0.325kg. (35.07 rad/s) k m m ¡ (c) By energy conservation, 1 2 2 kx m (the energy of the system at a turning point) is equal to
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