15. (a) Eq. 15-8 leads to 22123 m/s35.07 rad/s .0.100 maaxxωω−=−¡===Therefore,f= ω/2π= 5.58 Hz. (b) Eq. 15-12 provides a relation between (found in the previous part) and the mass: 2400 N/m=0.325kg.(35.07 rad/s)kmm¡(c) By energy conservation, 122kxm(the energy of the system at a turning point) is equal to
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