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Unformatted text preview: 21. Both parts of this problem deal with the critical case when the maximum acceleration
becomes equal to that of free fall. The textbook notes (in the discussion immediately after
Eq. 157) that the acceleration amplitude is am = ω2xm, where ω is the angular frequency;
this is the expression we set equal to g = 9.8 m/s2.
(a) Using Eq. 155 and T = 1.0 s, we have FG 2π IJ
HTK 2 xm = g xm = gT 2
= 0.25 m.
4π2 (b) Since ω = 2πf, and xm = 0.050 m is given, we find ( 2π f ) 2 xm = g f= 1
2π g
= 2.2 Hz.
xm ...
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics, Acceleration

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