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Unformatted text preview: 21. Both parts of this problem deal with the critical case when the maximum acceleration
becomes equal to that of free fall. The textbook notes (in the discussion immediately after
Eq. 15-7) that the acceleration amplitude is am = ω2xm, where ω is the angular frequency;
this is the expression we set equal to g = 9.8 m/s2.
(a) Using Eq. 15-5 and T = 1.0 s, we have FG 2π IJ
HTK 2 xm = g xm = gT 2
= 0.25 m.
4π2 (b) Since ω = 2πf, and xm = 0.050 m is given, we find ( 2π f ) 2 xm = g f= 1
= 2.2 Hz.
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