30. The total mechanical energy is equal to the (maximum) kinetic energy as it passes through the equilibrium position (x= 0): 12mv2= 12(2.0 kg)(0.85 m/s)2= 0.72 J. Looking at the graph in the problem, we see that U(x=10)=0.5 J. Since the potential
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.