ch15-p031 - 31. (a) Eq. 15-12 (divided by 2) yields f= 1 2...

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= 1 2 1 2 1000 500 225 f k m ππ == N/m kg Hz . .. (b) With x o = 0.500 m, we have Uk x 0 1 2 0 2 125 J . (c) With v o = 10.0 m/s, the initial kinetic energy is Km v 0 1 2 0 2 250 J . (d) Since the total energy E = K o + U o = 375 J is conserved, then consideration of the
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