Ch15-p034 - 34 We note that the ratio of Eq 15-6 and Eq 15-3 is v/x = tan(t where is 1 1 given by Eq 15-12 Since the kinetic energy is 2 mv2 and

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34. We note that the ratio of Eq. 15-6 and Eq. 15-3 is v / x = −ω tan( ω t + φ ) where ω is given by Eq. 15-12. Since the kinetic energy is 1 2 m v 2 and the potential energy is 1 2 kx 2 (which may be conveniently written as 1 2 m ω 2 x 2 ) then the ratio of kinetic to potential
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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