equal to the kinetic energy of the plate ( 12Iωm2where this ωmis the maximum angular speed of the plate, not the angular frequency ω). Noting that the maximum angular speed of the plate is ωm=ωθowhere ω= 2π/Twith T= 20 ms = 0.02 s as determined from the graph, then we can find the rotational inertial from 12Iωm2= 0.0093 J. Thus, 521.3 10 kg mI−=×⋅.54. We note that the initial angle is
This is the end of the preview. Sign up
access the rest of the document.