55. (a) The period of the pendulum is given by TImgd=2π/, where Iis its rotational inertia,m= 22.1 g is its mass, and dis the distance from the center of mass to the pivot point. The rotational inertia of a rod pivoted at its center is mL2/12 with L= 2.20 m. According to the parallel-axis theorem, its rotational inertia when it is pivoted a distance dfrom the center is I= mL2/12 + md2. Thus, TmLdmgdLdgd=+=+212212122222ππ(/).Minimizing T
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.