ch15-p055 - 55. (a) The period of the pendulum is given by...

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55. (a) The period of the pendulum is given by TI m g d = 2 π / , where I is its rotational inertia, m = 22.1 g is its mass, and d is the distance from the center of mass to the pivot point. The rotational inertia of a rod pivoted at its center is mL 2 /12 with L = 2.20 m. According to the parallel-axis theorem, its rotational inertia when it is pivoted a distance d from the center is I = mL 2 /12 + md 2 . Thus, T mL d mgd Ld gd = + = + 2 12 2 12 12 22 2 2 ππ (/ ) . Minimizing T
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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