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57. (a) We want to solve
e
–
bt
/2
m
= 1/3 for
t
. We take the natural logarithm of both sides to
obtain –
bt
/2
m
= ln(1/3). Therefore,
t
= –(2
m
/
b
) ln(1/3) = (2
m
/
b
) ln 3. Thus,
=
21
.50
0.230
3 =14.3 .
t
kg
kg / s
ln
s
a
f
(b) The angular frequency is
′
=−
=
−
=
ω
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics

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