70. (a) We note that ω = k/m = 1500/0.055 = 165.1 rad/s. We consider the most direct path in each part of this problem. That is, we consider in part (a) the motion directly from x 1 = +0.800 x m at time t 1 to x 2 = +0.600 x m at time t 2 (as opposed to, say, the block moving from x 1 = +0.800 x m through x = +0.600 x m , through x = 0, reaching x = – x m and after returning back through x = 0 then getting to x 2 = + 0.600 x m ). Eq. 15-3 leads to ω t 1 + φ = cos − 1 (0.800) = 0.6435 rad ω t 2 + φ = cos − 1 (0.600) = 0.9272 rad . Subtracting the first of these equations from the second leads to
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.