70. (a)
We note that
ω
=
k/m
=
1500/0.055
= 165.1 rad/s.
We consider the most direct path in each part of this problem.
That is, we consider in
part (a) the motion directly from
x
1
= +0.800
x
m
at time
t
1
to
x
2
= +0.600
x
m
at time
t
2
(as opposed to, say, the block moving from
x
1
= +0.800
x
m
through
x
= +0.600
x
m
, through
x
= 0, reaching
x
= –
x
m
and after returning back through
x
= 0 then getting to
x
2
=
+
0.600
x
m
).
Eq. 153 leads to
ω
t
1
+
φ
= cos
−
1
(0.800) = 0.6435 rad
ω
t
2
+
φ
= cos
−
1
(0.600) = 0.9272 rad .
Subtracting the first of these equations from the second leads to
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics

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