72. (a) The textbook notes (in the discussion immediately after Eq. 15-7) that the acceleration amplitude is am= ω2xm, where is the angular frequency (= 2πfsince there are 2πradians in one cycle). Therefore, in this circumstance, we obtain = 2 10000.00040=1.6 10. 242amπHzmm / safbg×(b) Similarly, in the discussion after Eq. 15-6, we find vm= xmso that = 2 10000.00040= 2.5. vmπHzmm / sch(c) From Eq. 15-8, we have (in absolute value) a= 2 10000.00020= 7.9 10. 232πHzmm / sbgch b
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.