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72. (a) The textbook notes (in the discussion immediately after Eq. 157) that the
acceleration amplitude is
a
m
=
ω
2
x
m
, where
is the angular frequency (
= 2
π
f
since
there are 2
π
radians in one cycle). Therefore, in this circumstance, we obtain
= 2 1000
0.00040
=1.6 10
.
2
42
a
m
π
Hz
m
m / s
af
bg
×
(b) Similarly, in the discussion after Eq. 156, we find
v
m
=
x
m
so that
= 2 1000
0.00040
= 2.5
.
v
m
π
Hz
m
m / s
ch
(c) From Eq. 158, we have (in absolute value)
a
= 2 1000
0.00020
= 7.9 10
.
2
32
π
Hz
m
m / s
b
g
c
h b
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics, Acceleration

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