22/23220.873s.2mRmRRTmgRgππ+===(b) We seek a value of r≠Rsuch that 222232RrgrRg+=and are led to the quadratic formula: rRRRRR=±−=3384222afor.Thus, our result is r= 0.126/2 = 0.0630 m. 74. (a) We use Eq. 15-29 and the parallel-axis theorem
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.