22
/2
3
2
2
0.873s.
2
mR
mR
R
T
mgR
g
ππ
+
==
=
(b) We seek a value of
r
≠
R
such that
2
2
2
2
3
2
Rr
gr
R
g
+
=
and are led to the quadratic formula:
r
RR
R
R
R
=
±−
=
33
8
42
2
2
a
f
or
.
Thus, our result is
r
= 0.126/2 = 0.0630 m.
74. (a) We use Eq. 1529 and the parallelaxis theorem
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics, Center Of Mass, Inertia, Mass

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