ch15-p075 - a 75. (a) The frequency for small amplitude...

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75. (a) The frequency for small amplitude oscillations is fg L = 12 // π a f , where L is the length of the pendulum. This gives f == 98 0 20 03 5 2 /( ./ ) / ( . ) .. π af ms m H z (b) The forces acting on the pendulum are the tension force G T of the rod and the force of gravity mg G . Newton’s second law yields G G G Tm gm a += , where m is the mass and G a is the acceleration of the pendulum. Let G G G aa a e =+ , where G a e is the acceleration of the elevator and G a is the acceleration of the pendulum relative to the elevator. Newton’s second law can then be written () e mg a T −+ = G GG ma G . Relative to the elevator the motion is exactly the same as it would be in an inertial frame where the acceleration due to gravity is
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