ch15-p076 - 76. Since the particle has zero speed...

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constant φ in Eq. 15-2 is zero. Also, f = 0.25 Hz is given, so we have ω = 2 π f = π /2 rad/s. The variable t is understood to take values in seconds. (a) The period is T = 1/ f = 4.0 s. (b) As noted above, = π /2 rad/s. (c) The amplitude, as observed above, is 0.37 cm. (d) Eq. 15-3 becomes x = (0.37 cm) cos( π t /2). (e) The derivative of x is v = –(0.37 cm/s)( π /2) sin( π t /2) (–0.58 cm/s) sin( π t /2). (f) From the previous part, we conclude v m = 0.58 cm/s. (g) The acceleration-amplitude is a m = 2 x m = 0.91 cm/s 2 . (h) Making sure our calculator is in radians mode, we find
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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