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80. (a) Comparing with Eq. 153, we see
ω
= 10 rad/s in this problem. Thus,
f
=
/2
π
=
1.6 Hz.
(b) Since
v
m
=
x
m
and
x
m
= 10 cm (see Eq. 153), then
v
m
= (10 rad/s)(10 cm) = 100 cm/s
or 1.0 m/s.
(c) The maximum occurs at
t
= 0.
(d) Since
a
m
=
2
x
m
then
v
m
= (10 rad/s)
2
(10 cm) = 1000 cm/s
2
or 10 m/s
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics

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