Since we are asked for the interval teq– twhere teqspecifies the instant the particle passes through the equilibrium position, then we set x= 0 and find =4+30 = 2.29 . 1teqcossππ−bgConsequently, the time interval is teq– t= 0.75 s. 81. (a) We require UE=12at some value of x. Using Eq. 15-21, this becomes 12=1212=2.22kxkxxxmmFHGIKJ¡We compare the given expression
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