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Since we are asked for the interval
t
eq
–
t
where
t
eq
specifies the instant the particle passes
through the equilibrium position, then we set
x
= 0 and find
=
4
+
3
0 = 2.29 .
1
t
eq
cos
s
π
π
−
bg
Consequently, the time interval is
t
eq
–
t
= 0.75 s.
81. (a) We require
U
E
=
1
2
at some value of
x
. Using Eq. 1521, this becomes
1
2
=
1
2
1
2
=
2
.
22
kx
kx
x
x
m
m
F
H
G
I
K
J
¡
We compare the given expression
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 Spring '08
 Any
 Physics

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