ch15-p085 - we have = 2 (2.00) = 4 rad/s (understood to be...

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85. (a) Hooke’s law readily yields k = (15 kg)(9.8 m/s 2 )/(0.12 m) = 1225 N/m. Rounding to three significant figures, the spring constant is therefore 1.23 kN/m. (b) We are told f = 2.00 Hz = 2.00 cycles/sec. Since a cycle is equivalent to 2 π radians,
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Unformatted text preview: we have = 2 (2.00) = 4 rad/s (understood to be valid to three significant figures). Using Eq. 15-12, we find ( ) 2 1225 N/m 7.76kg. 4 rad/s k m m = = = Consequently, the weight of the package is mg = 76.0 N....
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