ch15-p089 - 89. (a) The spring stretches until the...

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89. (a) The spring stretches until the magnitude of its upward force on the block equals the magnitude of the downward force of gravity: ky = mg , where y = 0.096 m is the elongation of the spring at equilibrium, k is the spring constant, and m = 1.3 kg is the mass of the block. Thus k = mg / y = (1.3 kg)(9.8 m/s 2 )/(0.096 m) = 1.33 ×10 2 N/m. (b) The period is given by 12 1 . 3 k g 2 2 0.62 s. 133 N / m m T fk π ππ ω == = = = (c) The frequency is f = 1/ T = 1/0.62 s = 1.6 Hz. (d) The block oscillates in simple harmonic motion about the equilibrium point determined by the forces of the spring and gravity. It is started from rest 5.0 cm below the equilibrium point so the amplitude is 5.0 cm.
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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