91. We note that for a horizontal spring, the relaxed position is the equilibrium position (in a regular simple harmonic motion setting); thus, we infer that the given v= 5.2 m/s at x= 0 is the maximum value vm(which equals ωxmwhere ==km/20rad/s).(a) Since = 2πf, we find f= 3.2 Hz. (b) We have vm= 5.2 m/s = (20 rad/s)xm, which leads to xm= 0.26 m. (c) With meters, seconds and radians understood, (0.26 m)cos(20
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.