ch15-p091 - 91. We note that for a horizontal spring, the...

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91. We note that for a horizontal spring, the relaxed position is the equilibrium position (in a regular simple harmonic motion setting); thus, we infer that the given v = 5.2 m/s at x = 0 is the maximum value v m (which equals ω x m where == km /2 0 r a d / s ) . (a) Since = 2 π f , we find f = 3.2 Hz. (b) We have v m = 5.2 m/s = (20 rad/s) x m , which leads to x m = 0.26 m. (c) With meters, seconds and radians understood, (0.26 m)cos(20
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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