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91. We note that for a horizontal spring, the relaxed position is the equilibrium position
(in a regular simple harmonic motion setting); thus, we infer that the given
v
= 5.2 m/s at
x
= 0 is the maximum value
v
m
(which equals
ω
x
m
where
==
km
/2
0
r
a
d
/
s
)
.
(a) Since
= 2
π
f
, we find
f
= 3.2 Hz.
(b) We have
v
m
= 5.2 m/s = (20 rad/s)
x
m
, which leads to
x
m
= 0.26 m.
(c) With meters, seconds and radians understood,
(0.26 m)cos(20
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics, Simple Harmonic Motion

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