ch15-p100 - 100. We note (from the graph) that am = 2xm =...

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100. We note (from the graph) that a m = ω 2 x m = 4.00 cm/s 2 . Also the value at t = 0 is a o = 1.00 cm/s 2 . Then Eq. 15-7 leads to φ = cos 1 (–1.00/4.00) = +1.82 rad or – 4.46 rad.
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