ch15-p108 - 108. Using Eq. 15-12, we find = k / m = 10 rad...

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(c) One interpretation of this question is “what is the most negative value of the acceleration?” in which case the answer is – a m = –30 m/s 2 . Another interpretation is “what is the smallest value of the absolute-value of the acceleration?” in which case the answer is zero. (d) Since the period is T = 2 π / ω = 0.628 s. Therefore, seven cycles of the motion requires
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