(c) One interpretation of this question is “what is the most negative value of the acceleration?” in which case the answer is –am= –30 m/s2. Another interpretation is “what is the smallest value of the absolute-value of the acceleration?” in which case the answer is zero. (d) Since the period is T= 2π/ω= 0.628 s. Therefore, seven cycles of the motion requires
This is the end of the preview. Sign up
access the rest of the document.