17. (a) The amplitude of the wave is ym=0.120 mm. (b) The wave speed is given by v= τμ, where τis the tension in the string and μis the linear mass density of the string, so the wavelength is λ= v/f= /fand the angular wave number is ()120.50kgm22100Hz141m .10Nkf−π==π=π=λ(c) The frequency is f= 100 Hz, so the angular frequency isω= 2π
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