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34. (a) We use Eq. 1626 and Eq. 1633 with
μ
= 0.00200 kg/m and
y
m
= 0.00300 m.
These give
v
=
τ / μ
= 775 m/s and
P
avg
=
1
2
μ
v
ω
2
y
m
2
= 10 W.
(b) In this situation, the waves are two separate string (no superposition occurs).
The
answer is clearly twice that of part (a);
P
= 20 W.
(c) Now they are on the same string.
If they are interfering constructively (as in Fig. 16
16(a)) then the amplitude
y
m
is doubled which means its square
y
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics

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