1. Let
T
L
be the temperature and
p
L
be the pressure in the lefthand thermometer.
Similarly, let
T
R
be the temperature and
p
R
be the pressure in the righthand thermometer.
According to the problem statement, the pressure is the same in the two thermometers
when they are both at the triple point of water. We take this pressure to be
p
3
. Writing Eq.
185 for each thermometer,
33
(273.16K)
and
(273.16K)
,
LR
LR
pp
TT
p
p
§·
§·
==
¨¸
¨¸
©¹
©¹
we subtract the second equation from the first to obtain
3
(273.16K)
.
LR
LR
p
p
TT
p
§·
−
−=
¨¸
©¹
First, we take
T
L
= 373.125 K (the boiling point of water) and
T
R
= 273.16 K (the triple
point of water). Then,
p
L
–
p
R
= 120 torr. We solve
3
120torr
373.125K
273.16K
(273.16K)
p
§·
−=
¨¸
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics

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