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19. The initial volume
V
0
of the liquid is
h
0
A
0
where
A
0
is the initial crosssection area
and
h
0
= 0.64 m. Its final volume is
V = hA
where
h – h
0
is what we wish to compute.
Now, the area expands according to how the glass expands, which we analyze as follows:
Using
2
Ar
π
=
, we obtain
()
2
22
2
(
)
2
dA
r dr
r r dT
r dT
AdT
ππ
αα
α
==
=
=
.
Therefore, the height is
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics

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