Ch18-p019 - 19 The initial volume V0 of the liquid is h0A0 where A0 is the initial cross-section area and h0 = 0.64 m Its final volume is V = hA

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19. The initial volume V 0 of the liquid is h 0 A 0 where A 0 is the initial cross-section area and h 0 = 0.64 m. Its final volume is V = hA where h – h 0 is what we wish to compute. Now, the area expands according to how the glass expands, which we analyze as follows: Using 2 Ar π = , we obtain () 2 22 2 ( ) 2 dA r dr r r dT r dT AdT ππ αα α == = = . Therefore, the height is
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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