Unformatted text preview: Now, following the same procedure as shown in Sample Problem 184, we find c A m A ( T f − T A ) + c B m B ( T f − T B ) = 0 c A (5.0 kg)(40°C – 100°C) + (4000 J/kg·C°)(1.5 kg)(40°C – 20°C) = 0 which leads to c A = 4.0×10 2 J/kg·K....
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics, Heat

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