ch18-p038 - 38. The heat needed is found by integrating the...

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15.0 C 2 5.0 C 15.0 23 5.0 (2.09) (0.20 0.14 0.023 ) (2.0)(0.20 0.070 0.00767 ) (cal) 82cal. ff ii TT Qc m d T m c d T T T d T T ° ° == = + + =+ + = ³³ ³
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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