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W
=
W
AB
+
W
BC
+
W
CA
= 60 J – 90 J + 0 = –30 J
and the total heat absorbed is
Q
=
W
= –30 J. This means the gas loses 30 J of energy in
the form of heat.
43. Over a cycle, the internal energy is the same at the beginning and end, so the heat
Q
absorbed equals the work done:
Q
=
W
. Over the portion of the cycle from
A
to
B
the
pressure
p
is a linear function of the volume
V
and we may write
3
10
20
Pa +
Pa/m
,
33
p
V
§·
=
¨¸
©¹
where the coefficients were chosen so that
p
= 10 Pa when
V
= 1.0 m
3
and
p
= 30 Pa
when
V
= 4.0 m
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics, Energy, Work, Heat

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