ch18-p050 - individual parts of the cycle Q AB + Q BC + Q...

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50. Since the process is a complete cycle (beginning and ending in the same thermodynamic state) the change in the internal energy is zero and the heat absorbed by the gas is equal to the work done by the gas: Q = W . In terms of the contributions of the
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Unformatted text preview: individual parts of the cycle Q AB + Q BC + Q CA = W and Q CA = W Q AB Q BC = +15.0 J 20.0 J 0 = 5.0 J. This means 5.0 J of energy leaves the gas in the form of heat....
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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