ch18-p057 - 57. We use Pcond = kAT/L A/L. Comparing cases...

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57. We use P cond = kA Δ T / L A / L . Comparing cases ( a ) and ( b ) in Figure 18–44, we have cond cond cond 4. ba a ab AL PP P §· == ¨¸ ©¹ Consequently, it would take 2.0 min/4 = 0.50 min for the same amount of heat to be
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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